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Sahithyan's S2
Sahithyan's S2 — Methods of Mathematics

Counting Outcomes

Combination

A selection of a set of objects, regardless of the selection order.

Permutation

A linear arrangement of a set of objects, with regard to the order of the arrangement.

Circular Permutation

A circular arrangement of a set of objects, with regard to the order of the arrangement. Unlike linear arrangements, circular permutations do not have a fixed starting point.

Rule 1

Suppose there is an experiment consisting of kk number of steps. And ii-th step having nin_i number of outcomes.

Total number of outcomes=i=1kni\text{Total number of outcomes} = \prod_{i=1}^k {n_i}

Rule 2

Total number of combinations of nn objects taken rr at a time is:

nCr=n!(nr)!  r!^nC_r = \frac{n!}{(n-r)!\; r!}

Rule 3

The number of permutations of nn objects taken rr at a time is:

nPr=n!(nr)!^nP_r = \frac{n!}{(n-r)!}

Rule 4

The number of circular permutations of rr objects taken from a group of nn objects:

nPrr=nCr×(r1)!\frac{^nP_r}{r} = {}^nC_r \times (r-1)!

Total number of linear permutations are divided by rr, the number of objects being arranged, to eliminate equivalent rotations.

Alternatively, it can be expressed as the product of the number of combinations, nCr{}^nC_r, and the factorial of (r1)(r-1), which represents the number of ways to arrange the remaining objects after fixing one as a reference point.

Rule 5

Suppose a multi-set MM contains nn items of kk different types. There are rir_i number of type ii objects. Total number of distinct permutations:

n!i=1kri!\frac{n!}{\prod_{i=1}^k {r_i!}}

Rule 6

Suppose a multi-set MM contains nn items of kk different types. There are rir_i number of type ii objects. Total number of distinct combinations (of all sizes):

i=1k(ri+1)\prod_{i=1}^k (r_i + 1)

This includes an empty set as well.