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Sahithyan's S2
Sahithyan's S2 — Methods of Mathematics

Differentiability

Equation of tangent line

Suppose ff is a single-variable function, and ff is differentiable at x0x_0. The equation of the tangent line to ff at x0x_0 is:

yf(x0)=f(x0)(xx0)y - f(x_0) = f'(x_0)(x - x_0)

For 2-variable functions, they will have a tangent plane. For functions with more than 2 variables, they have a tangent space.

Differentiable

Suppose z=f(x,y)z=f(x,y) where f:DRf:D\rightarrow \mathbb{R}; DR2D\subset \mathbb{R}^2 and (a,b)D(a,b)\in D.

If fx(a,b)f_x(a,b) and fy(a,b)f_y(a,b) exists and Δz\Delta{z} can be expressed in the below form, then ff is differentiable at (a,b)(a,b).

Δz=Δxfx(a,b)+Δyfy(a,b)+ϵ1Δx+ϵ2Δy\Delta z = \Delta x f_x(a,b) + \Delta y f_y(a,b) + \epsilon_1\Delta x + \epsilon_2 \Delta y

where ϵ1\epsilon_1 and ϵ2\epsilon_2 approach 00 as (Δx,Δy)(\Delta x, \Delta y) approach (0,0)(0,0). OR

ff is differentiable at (a,b)(a,b) iff the limit exists:

lim(x,y)(a,b)f(x,y)f(a,b)fx(a,b)Δxfy(a,b)Δy(xa)2+(yb)2\lim_{(x,y)\to(a,b)} \frac{f(x,y)-f(a,b)-f_x(a,b)\Delta x -f_y(a,b)\Delta y }{\sqrt{(x-a)^2+(y-b)^2}}

ff is said to be differentiable iff it is differentiable at every point in its domain.

If either fxf_{x} or fyf_y is non-existent at a point, then ff is not differentiable at that point.

If fxf_x and fyf_y are continuous throughout at an open region DD, then ff is differentiable at every point of DD.

The differentiability can also be proven by proving:

limΔρ0ΔzdzΔρ=0      where      Δρ=Δx2+Δy2\lim_{\Delta \rho \to 0} \frac{\Delta z - \text{d}z}{\Delta \rho} = 0 \;\;\; \text{where} \;\;\; \Delta \rho = \sqrt{{\Delta x}^2 + {\Delta y}^2}

Implies Continuity

f is differentiable    f is continousf \text{ is differentiable} \implies f \text{ is continous}

Derivative

Suppose z=f(x,y)z=f(x,y) where ff is a differentiable function of xx and yy.

dz=zxdx+zydy=Δxfx(a,b)+Δyfy(a,b)\text{d}z = \frac{\partial z}{\partial x}\,\text{d}x + \frac{\partial z}{\partial y}\,\text{d}y =\Delta x f_x(a,b) + \Delta y f_y(a,b)

dz\text{d}z is called the total differential of ff.

Chain Rule

Let x(t),y(t)x(t),y(t) be single-variable, differentiable functions and f(x,y)f(x,y) be a 2-variable differentiable function having continuous first order partial derivatives.

f(x(t),y(t))f\big(x(t),y(t)\big) is differentiable.

dfdt=fxdxdt+fydydt\frac{\text{d}f}{\text{d}t} = \frac{\partial f}{\partial x}\frac{\text{d}x}{\text{d}t} + \frac{\partial f}{\partial y}\frac{\text{d}y}{\text{d}t}

Can be extended for functions of more than 2 variables.